15k^2+8k+1=0

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Solution for 15k^2+8k+1=0 equation: 



15k^2+8k+1=0

a = 15; b = 8; c = +1;
Δ = b2-4ac
Δ = 82-4·15·1
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$


$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2}{2*15}=\frac{-10}{30}
=-1/3
$


$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2}{2*15}=\frac{-6}{30}
=-1/5
$

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